The wavelengths of light used in an optical i | vedclass

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(D) The resolving power $(RP)$ of an optical instrument is inversely proportional to the wavelength $(\lambda)$ of the light used, i.e., $RP \propto \

Vedclass · Accepted Answer

$5 : 4$

Vedclass · Answer

(D) The resolving power $(RP)$ of an optical instrument is inversely proportional to the wavelength $(\lambda)$ of the light used, i.e., $RP \propto \frac{1}{\lambda}$.Given $\lambda_1 = 4000\,\mathring{A}$ and $\lambda_2 = 5000\,\mathring{A}$.The ratio of their resolving powers is $\frac{RP_1}{RP_2} = \frac{\lambda_2}{\lambda_1}$.Substituting the values, we get $\frac{RP_1}{RP_2} = \frac{5000}{4000} = \frac{5}{4}$.Therefore, the ratio is $5 : 4$.

The wavelengths of light used in an optical instrument are ${\lambda _1} = 4000\,\mathring{A}$ and ${\lambda _2} = 5000\,\mathring{A}$. The ratio of their respective resolving powers (corresponding to ${\lambda _1}$ and ${\lambda _2}$) is:

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